已知大小typedefed数组的c ++函数模板专门化 [英] c++ function template specialization for known size typedefed array
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问题描述
请考虑以下代码:
#include <iostream>
#include <typeinfo>
template< typename Type >
void func( Type var )
{
std::cout << __FUNCTION__ << ": var = " << var << " [" << typeid( var ).name( ) << "]." << std::endl;
std::cout << "-> var is SCALAR. Size = " << sizeof( Type ) << std::endl;
}
#if 1
template< typename Type >
void func( Type * var )
{
std::cout << __FUNCTION__ << ": var = " << var << " [" << typeid( var ).name( ) << "]." << std::endl;
std::cout << "-> var is ARRAY. Size = " << sizeof( Type * ) << std::endl;
}
#endif
int main( )
{
typedef char char16[ 16 ];
char16 c16 = "16 bytes chars.";
std::cout << "Size of char16 = " << sizeof( char16 ) << std::endl;
func( c16 );
return 0;
}
如果我编译并运行,我看到:
If I compile it and run, I see this:
> g++ -Wall -g3 spec_f_pointer.cpp -o spec_f_pointer
> ./spec_f_pointer
Size of char16 = 16
func: var = 16 bytes chars. [Pc].
-> var is ARRAY. Size = 8
很明显, sizeof
func
指的是指针的大小,而不是 typedef
数组的大小,如 main()
。
Clearly the sizeof
printed inside func
refers to the size of a pointer, and not the size of the typedef
array, as given in main()
.
现在我不知道如何正确地做出让 func <
Now I wonder how to correctly do the trick for getting my func
to specialize in such a way that it correctly knows about my typedef and its size.
有人在这里可以帮助我吗?
Does anyone here can help me, please?
非常感谢。
EDIT
实现专业化:
template< typename Type >
void func( Type * const &var )
{
std::cout << __FUNCTION__ << ": var = " << var << " [" << typeid( var ).name( ) << "]." << std::endl;
std::cout << "-> var is ARRAY. Size = " << sizeof( Type * ) << std::endl;
}
输出为:
Size of char16 = 16
func: var = 16 bytes chars. [A16_c].
-> var is SCALAR. Size = 16
我注意到 Pc
到 A16_c
。
推荐答案
如果你想将数组的函数专门化,可以这样做:
If you want to specialize your function for arrays, do this:
template<typename T, int N>
void func(T(&var)[N])
{
typedef T Type[N];
std::cout << __FUNCTION__ << " [" << typeid( var ).name( ) << "]." << std::endl;
std::cout << "-> var is ARRAY. Size = " << sizeof( Type ) << std::endl;
std::cout << "Number of elements: " << N << std::endl;
std::cout << "Size of each element: " << sizeof(T) << std::endl;
}
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