何时删除模板实例化而不是删除非模板超载？ [英] When is deleting a template instantiation preferable to deleting a non-template overload?

问题描述

假设我有一个使用原始指针的模板：

Suppose I have a template that works with raw pointers:

template<typename T>
void processPointer(T* ptr);

我不想使用 void * 指针。看来我有两个选择。我可以删除一个非模板的重载：

I don't want this to be called with void* pointers. It seems I have two choices. I can delete a non-template overload:

void processPointer(void*) = delete;

或者我可以删除模板实例化：

Or I can delete a template instantiation:

template<>
void processPointer<void>(void*) = delete;

声明非模板重载更容易（不用尖括号括起来）。是否有理由为什么我想要删除模板实例化？

Declaring the non-template overload is easier (no futzing with angle brackets). Are there reasons why I'd prefer to delete the template instantiation instead?

推荐答案

这里有一个原因喜欢模板版本： processPointer< void>（void *）直接，避免其他重载。

Here's one reason to favor the template version: processPointer<void>(void*) can still be invoked directly, avoiding the other overload.

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