为什么禁止打开多个命名空间? [英] Why is it forbidden to open multiple namespaces at a stretch?
问题描述
可以使用命名空间foo :: bar; (即,使用内部命名空间而不使用外部命名空间首先/所有),为什么标准禁止要执行以下操作?
It's possible to do using namespace foo::bar;
(i.e., using the inner namespace without using the outer namespace first / at all), why does the standard forbid to do the following?
namespace foo::bar {
// open nested namespace bar in foo and extend it...
}
我不是在寻找解决方法,只是一个可能的理性为什么不允许这样做。
I'm not looking for a workaround, just a possible rational on why this isn't allowed.
推荐答案
我不确定禁止是正确的词 - 也许它只是监督。
I'm not sure "forbidden" is the right word - maybe it was just an oversight. It's a fairly small nice-to-have which isn't really a big deal.
你也可以认为命名空间是一个非常小的好处,写
,因此允许该语法看起来像 foo :: bar
时,尚未创建foo foo
。
You could also take the point of view that the namespace foo
isn't created yet when you write foo::bar
, so allowing that syntax makes it look like foo
was already created when it was not.
您还可以进一步请求写入 class Foo :: MyClass {...
在命名空间 Foo
中定义 MyClass
,变量等,但这个功能真的有必要,并解决任何特定的紧迫问题吗?
You could also go further and request the ability to write class Foo::MyClass {...
to define MyClass
in namespace Foo
, and the same for functions, variables, etc. But is this feature really necessary and solving any particular pressing problem?
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