gdb找不到运算符[] [英] gdb Could not find operator[]

问题描述

double var1, var2;
std::vector<double *> x;

var1 = 1;
var2 = 2;

x.push_back(&var1);
x.push_back(&var2);

当我在gdb中调试这个代码并尝试打印x [0]或* x [0] get：找不到operator []。
现在如果我在push_back之后包含这行：

When I debug this code in gdb and try print x[0] or *x[0] I get: Could not find operator[]. Now if I include this line after the push_back:

x[0] = &var1;

我可以访问gdb中的任何特定元素。同样的事情发生在其他成员，如front（），at（）等。我的理解是，编译器/链接器只包含成员函数存在于源代码，那些是我可以在gdb中使用。有没有办法包括std :: vector的每个成员函数，所以我可以访问他们在gdb？

I can access any specific elements in gdb. Same thing happens with other members such as front(), at(), etc. My understanding is that the compiler/linker includes only the member functions present in the source code and those are the ones I can use in gdb. Is there a way to include every member function of std::vector so I can access them in gdb?

推荐答案

我的理解是，编译器/链接器只包含源代码中存在的成员函数，那些是我可以在gdb中使用的。

My understanding is that the compiler/linker includes only the member functions present in the source code and those are the ones I can use in gdb.

您的理解不正确/不完整。

Your understanding is incorrect / incomplete.

std :: vector 是一个模板类。没有显式实例化，编译器需要实例化所调用的方法（通常是源中存在的方法的子集）。

std::vector is a template class. Without explicit instantiation, the compiler is required to instantiate only the methods called (usually a subset of methods present in the source).

有没有办法包括std :: vector的每个成员函数，所以我可以在gdb中访问它们。

Is there a way to include every member function of std::vector so I can access them in gdb?

对于给定类型 T ，您应该能够为 T 整个向量>，请求它，例如：

For a given type T, you should be able to explicitly instantiate entire vector for that T, by requesting it, e.g.:

template class std::vector<double>;

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