部分模板的C ++ typedef [英] C++ typedef for partial templates

问题描述

我需要这样做一个typedef。

i need to do a typedef like this.

template< class A, class B, class C >
class X
{
};

template< class B, class C >
typedef X< std::vector<B>, B, C >  Y;

我发现它不支持C ++。

I just found that it is not supported in C++. Can someone advise me on how to achieve the same through alternative means?

感谢，
Gokul。

Thanks, Gokul.

推荐答案

如果你有一个C ++ 0x / C ++ 1x编译器，将允许与略有不同的语法（看起来好像编译器不支持此功能） ：

If you have a C++0x/C++1x compiler, that will be allowed with a slightly different syntax (it seems as if compilers don't still support this feature):

template <typename B, typename C>
using Y = X< std::vector<B>, B, C >;

您可以使用其他技术，例如在模板化结构中定义一个封闭类型或者滥用继承（如果可能避免）：

You can use other techniques, like defining an enclosed type in a templated struct (like Pieter suggests), or abusing inheritance (avoid if possible):

template <typename B, typename C>
class Y : public X< std::vector<B>, B, C > {};

这篇关于部分模板的C ++ typedef的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！