快速1 / X分频（倒数） [英] Fast 1/X division (reciprocal)

问题描述

如果精确度不重要，是否有某种方法可以改善相对于速度的倒数（除以1除以X）。

Is there some way to improve reciprocal (division 1 over X) with respect to speed, if the precision is not crucial?

所以，我需要计算1 / X。有没有一些解决方法，所以我失去精度，但更快？

So, I need to calculate 1/X. Is there some workaround so I lose precision but do it faster?

推荐答案

首先，确保这不是一个过早优化。你知道这是你的瓶颈吗？

First, make sure this isn't a case of premature optimization. Do you know that this is your bottleneck?

如Mystical所说，1 / x可以很快计算。请确保您未对1或除数使用 double 数据类型。浮动快得多。

As Mystical says, 1/x can be calculated very quickly. Make sure you're not using double datatype for either the 1 or the divisor. Floats are much faster.

这就是说，基准，基准，基准。不要浪费你的时间花费数小时的理论，只是为了发现糟糕的性能的来源是IO访问。

That said, benchmark, benchmark, benchmark. Don't waste your time spending hours on numerical theory just to discover the source of the poor performance is IO access.

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