在C ++ 11中等待多个条件变量的最好方法是什么？ [英] What is the best way to wait on multiple condition variables in C++11?
问题描述
第一个上下文：我正在学习C ++ 11中的线程，为此，我试图构建一个小 actor 类，基本上（我离开异常处理和传播的东西出来）如下：
First a little context: I'm in the process of learning about threading in C++11 and for this purpose, I'm trying to build a small actor class, essentially (I left the exception handling and propagation stuff out) like so:
class actor {
private: std::atomic<bool> stop;
private: std::condition_variable interrupt;
private: std::thread actor_thread;
private: message_queue incoming_msgs;
public: actor()
: stop(false),
actor_thread([&]{ run_actor(); })
{}
public: virtual ~actor() {
// if the actor is destroyed, we must ensure the thread dies too
stop = true;
// to this end, we have to interrupt the actor thread which is most probably
// waiting on the incoming_msgs queue:
interrupt.notify_all();
actor_thread.join();
}
private: virtual void run_actor() {
try {
while(!stop)
// wait for new message and process it
// but interrupt the waiting process if interrupt is signaled:
process(incoming_msgs.wait_and_pop(interrupt));
}
catch(interrupted_exception) {
// ...
}
};
private: virtual void process(const message&) = 0;
// ...
};
每个actor都运行在自己的 actor_thread 等待在 incoming_msgs 上的新传入消息，以及 - 当消息到达时，处理它。
Every actor runs in its own actor_thread, waits on a new incoming message on incoming_msgs and -- when a message arrives -- processes it.
actor_thread 与 actor 必须与它一起死，这就是为什么我需要某种中断机制在 message_queue :: wait_and_pop（std :: condition_variable中断）。
The actor_thread is created together with the actor and has to die together with it, which is why I need some kind of interrupt mechanism in the message_queue::wait_and_pop(std::condition_variable interrupt).
基本上，我需要 wait_and_pop 阻塞，直到
a）a new 消息到达或
b），直到中断被触发，在这种情况下 - 理想地 - interrupted_exception
Essentially, I require that wait_and_pop blocks until either
a) a new message arrives or
b) until the interrupt is fired, in which case -- ideally -- an interrupted_exception is to be thrown.
新消息到达 message_queue 目前还由 std :: condition_variable new_msg_notification ：
// ...
// in class message_queue:
message wait_and_pop(std::condition_variable& interrupt) {
std::unique_lock<std::mutex> lock(mutex);
// How to interrupt the following, when interrupt fires??
new_msg_notification.wait(lock,[&]{
return !queue.empty();
});
auto msg(std::move(queue.front()));
queue.pop();
return msg;
}
为了简化故事，问题是这样的：当中断 new_msg_notification.wait（...） >
To cut the long story short, the question is this: How do I interrupt the waiting for a new message in new_msg_notification.wait(...) when the interrupt is triggered (without introducing a time-out)?
或者，问题可以解读为：如何等待两个
Alternatively, the question may be read as: How do I wait until any one of two std::condition_variables are signaled?
一个朴素的方法似乎不是使用 std :: condition_variable 原子标志 std :: atomic< bool>中断然后忙于等待 new_msg_notification ，只有一个非常小的超时，直到一个新消息到达或直到 true == interrupted 。
One naive approach seems to be not to use std::condition_variable at all for the interrupt and instead just use an atomic flag std::atomic<bool> interrupted and then busy wait on new_msg_notification with a very small time-out until either a new message has arrived or until true==interrupted. However, I would very much like to avoid busy waiting.
从pilcrow的评论和回答看，基本上有两种方法可能。
From the comments and the answer by pilcrow, it looks like there are basically two approaches possible.
- 终止消息，由Alan，mukunda和pilcrow提出。我决定反对这个选项，因为我不知道在我想要actor终止的队列的大小。它可能是非常好的（因为它是大多数情况下，当我想要的东西快速终止），有成千上万的消息留在队列中处理，似乎不可接受等待他们被处理，直到终止消息得到它
- 实现条件变量的自定义版本，可能会被另一个线程中断，将通知转发到第一个线程正在等待的条件变量。我选择了这种方法。
对于你感兴趣的人，我的实现如下。我的情况下的条件变量实际上是一个信号量（因为我更喜欢他们，因为我喜欢这样做的练习）。我为这个信号量配备了一个相关的中断，它可以通过 semaphore :: get_interrupt（）从信号量获取。如果现在一个线程阻塞在 semaphore :: wait（），另一个线程有可能调用 semaphore :: interrupt :: trigger（） code>在信号量的中断，导致第一个线程解除阻塞并传播 interrupt_exception 。
For those of you interested, my implementation goes as follows. The condition variable in my case is actually a semaphore (because I like them more and because I liked the exercise of doing so). I equipped this semaphore with an associated interrupt which can be obtained from the semaphore via semaphore::get_interrupt(). If now one thread blocks in semaphore::wait(), another thread has the possibility to call semaphore::interrupt::trigger() on the interrupt of the semaphore, causing the first thread to unblock and propagate an interrupt_exception.
struct
interrupt_exception {};
class
semaphore {
public: class interrupt;
private: mutable std::mutex mutex;
// must be declared after our mutex due to construction order!
private: interrupt* informed_by;
private: std::atomic<long> counter;
private: std::condition_variable cond;
public:
semaphore();
public:
~semaphore() throw();
public: void
wait();
public: interrupt&
get_interrupt() const { return *informed_by; }
public: void
post() {
std::lock_guard<std::mutex> lock(mutex);
counter++;
cond.notify_one(); // never throws
}
public: unsigned long
load () const {
return counter.load();
}
};
class
semaphore::interrupt {
private: semaphore *forward_posts_to;
private: std::atomic<bool> triggered;
public:
interrupt(semaphore *forward_posts_to) : triggered(false), forward_posts_to(forward_posts_to) {
assert(forward_posts_to);
std::lock_guard<std::mutex> lock(forward_posts_to->mutex);
forward_posts_to->informed_by = this;
}
public: void
trigger() {
assert(forward_posts_to);
std::lock_guard<std::mutex>(forward_posts_to->mutex);
triggered = true;
forward_posts_to->cond.notify_one(); // never throws
}
public: bool
is_triggered () const throw() {
return triggered.load();
}
public: void
reset () throw() {
return triggered.store(false);
}
};
semaphore::semaphore() : counter(0L), informed_by(new interrupt(this)) {}
// must be declared here because otherwise semaphore::interrupt is an incomplete type
semaphore::~semaphore() throw() {
delete informed_by;
}
void
semaphore::wait() {
std::unique_lock<std::mutex> lock(mutex);
if(0L==counter) {
cond.wait(lock,[&]{
if(informed_by->is_triggered())
throw interrupt_exception();
return counter>0;
});
}
counter--;
}
使用 semaphore ，我的消息队列实现现在看起来像这样（使用信号量而不是 std :: condition_variable 我可以摆脱 std :: mutex ：
Using this semaphore, my message queue implementation now looks like this (using the semaphore instead of the std::condition_variable I could get rid of the std::mutex:
class
message_queue {
private: std::queue<message> queue;
private: semaphore new_msg_notification;
public: void
push(message&& msg) {
queue.push(std::move(msg));
new_msg_notification.post();
}
public: const message
wait_and_pop() {
new_msg_notification.wait();
auto msg(std::move(queue.front()));
queue.pop();
return msg;
}
public: semaphore::interrupt&
get_interrupt() const { return new_msg_notification.get_interrupt(); }
};
我的 actor 现在能够在其线程中以非常低的延迟中断其线程。目前的实现如下：
My actor, is now able to interrupt its thread with very low latency in its thread. The implementation presently like this:
class
actor {
private: message_queue
incoming_msgs;
/// must be declared after incoming_msgs due to construction order!
private: semaphore::interrupt&
interrupt;
private: std::thread
my_thread;
private: std::exception_ptr
exception;
public:
actor()
: interrupt(incoming_msgs.get_interrupt()), my_thread(
[&]{
try {
run_actor();
}
catch(...) {
exception = std::current_exception();
}
})
{}
private: virtual void
run_actor() {
while(!interrupt.is_triggered())
process(incoming_msgs.wait_and_pop());
};
private: virtual void
process(const message&) = 0;
public: void
notify(message&& msg_in) {
incoming_msgs.push(std::forward<message>(msg_in));
}
public: virtual
~actor() throw (interrupt_exception) {
interrupt.trigger();
my_thread.join();
if(exception)
std::rethrow_exception(exception);
}
};
推荐答案
您问：
在C ++ 11中等待多个条件变量的最佳方法是什么？
您不能，必须重新设计。一个线程可以一次只等待一个条件变量（及其关联的互斥体）。在这方面，用于同步的Windows设施比POSIX样式同步原语族更加丰富。
You can't, and must redesign. One thread may wait on only one condition variable (and its associated mutex) at a time. In this regard the Windows facilities for synchronization are rather richer than those of the "POSIX-style" family of synchronization primitives.
线程安全队列的典型方法是入列一个特别的全部完成！消息，或设计可断开（或可关闭）队列。在后一种情况下，队列的内部条件变量保护一个复杂的谓词：一个项目可用或队列已被破坏。
The typical approach with thread-safe queues is to enqueue a special "all done!" message, or to design a "breakable" (or "shutdown-able") queue. In the latter case, the queue's internal condition variable then protects a complex predicate: either an item is available or the queue has been broken.
在评论中，您发现
如果没有人在等待，notify_all / p>
a notify_all() will have no effect if there is no one waiting
这是真的，但可能不相关。 wait（）对条件变量也意味着检查一个谓词，并且在实际阻止通知之前检查它。因此，工作线程忙于处理一个未命中一个 notify_all（）的队列项，将在下次检查队列条件时看到谓词可用，或者，队列已完成）已更改。
That's true but probably not relevant. wait()ing on a condition variable also implies checking a predicate, and checking it before actually blocking for a notification. So, a worker thread busy processing a queue item that "misses" a notify_all() will see, the next time it inspects the queue condition, that the predicate (a new item is available, or, the queue is all done) has changed.
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