C ++中的int *和int []之间的差异 [英] Difference between int* and int[] in C++

问题描述

上下文：C ++
考虑下面的例子

Context: C++ Consider the example below

class TestClass
{
private:
    int A[];
    int *B;

public:
    TestClass();
};

TestClass::TestClass()
{
    A = 0; // Fails due to error: incompatible types in assignment of `int' to `int[0u]'
    B = 0; // Passes
}

A = 0失败，但B = 0成功。什么是捕获？ A是什么？常量指针？

A = 0 fails but B = 0 succeeds. What's the catch? What exactly is A? A constant pointer? How do I initialize it then?

推荐答案

它们之间的唯一区别是 int A [] 不能编译，而且不应该编译！

The only difference between them is that int A[] in a class would not compile, and should not compile!

"ComeauTest.c", line 4: error:   
incomplete type is not allowed   
      int A[];
          ^ 

Wikipedia 说，

Comeau C / C ++已被视为
最符合标准的C ++
编译器。

会建议：即使您的编译器编译，也不要编写此类代码。

I therefore would suggest : Don't write such code even if your compiler compiles it.

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