在SWIG for Python中包装boost :: shared_ptr的std :: vector [英] Wrapping std::vector of boost::shared_ptr in SWIG for Python

问题描述

编辑：解决了，我的错误;

  std： ：vector& boost :: shared_ptr<实体> >实体; 
  

，我尝试通过SWIG公开它：

 ％includeboost_shared_ptr.i
％includestd_vector.i
 
％shared_ptr（Entity）
％ include< Entity.h> 
 
 namespace std {
％template（EntityVector）vector< boost :: shared_ptr< Entity> > ;; 
}; 
 
％include< TheFileWithEntities.h>但是，在Python实体最终是一个元组：
 
 $ b 
 
 
  import MyModule 
打印类型（MyModule.cvar.entities）
＃输出:(类型'tuple'）
  
我已经为此搜索了，但没有找到任何具体的例子如何包装。一个页面给了一个小例子，为C＃封装它，但它在我的情况下没有帮助。
 
 
 
任何帮助是非常感激。
解决方案
 SWIG似乎将std :: vector的全局变量包装到元组中。解决方案是将实体移动到类中，并通过该类的实例访问它。示例：
  class Globals 
 {
 public：
 std :: vector< boost :: shared_ptr<实体> >实体; 
}; 
 
 extern全局变量
  
 
EDIT: Solved, my mistake; explained in my answer.

I have this:
std::vector < boost::shared_ptr < Entity > > entities;
and I try to expose it through SWIG like this:
%include "boost_shared_ptr.i"
%include "std_vector.i"

%shared_ptr(Entity)
%include <Entity.h>

namespace std {
    %template(EntityVector) vector<boost::shared_ptr<Entity> >;
};

%include <TheFileWithEntities.h>
However, in Python entities ends up being a tuple:
import MyModule
print type(MyModule.cvar.entities)
# Output: (type 'tuple')
I've Googled for this, but could not find any concrete examples on how to wrap this. One page gave a small example for wrapping it for C#, but it didn't help in my case.

Any help is greatly appreciated.
解决方案
SWIG seems to wrap global variables of type std::vector into tuples. The solution is to move entities into a class, and access it through an instance of that class. Example:
class Globals
{
public:
     std::vector < boost::shared_ptr < Entity > > entities;
};

extern Globals globals;


                        
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