新的C ++返回语法有限吗？ [英] Is the new C++ return syntax limited?

问题描述

我开始了一个新的私人项目，并决定使用更多 C ++ 11 / 14 。所以我也开始使用新的返回语法

I started a new private project and decided to use more C++11/14 this time. So I also started using the new return syntax

auto functionName() -> returnType;

它大部分工作很好，但现在我需要一些错误处理，如何重写这样的东西：

It works for the most part very well, but now I needed some error handling and could not find out how to re-write stuff like this:

virtual const char* what() const noexcept override;

在某些情况下，新的语法不能使用，或者我只是不够聪明到找到正确的顺序？对我来说，重要的是保持一致，所以我希望问题更多在我身边。

with the new syntax. Are there some cases where the new syntax can not be used or am I only not clever enough to find the right order? For me it is important to keep things consistent, so I hope the problem is more on my side.

推荐答案

virtual auto what() const noexcept -> const char * override;

这只是你必须使用的顺序。语法可能不同，可能，但这是我们有。

This is just the order you have to use. The syntax could have been different, probably, but this is what we've got.

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