单例模式 - 早期绑定（涉及静态变量）是否减少了互斥锁的需要？ [英] Singleton pattern - Does early binding (with static variables involved) diminish the need of mutex locks?

问题描述

他们说早期绑定解决了同步的问题。我不明白怎么样。这是Java的特别的东西还是同样适用于C ++？

They say that early binding solves the problem of synchronization. I couldn't understand "how". Is this something special to Java or the same applies to C++ too?

所以，这个方法我们实际上不需要互斥锁？

so, with this method we actually won't require a mutex lock?

推荐答案

我认为他们指的是在开始/创建任何线程之前创建Singleton实例，从而减少创建时的同步需求。

I think they are referring to creating the Singleton instance before starting/creating any threads, thus alleviating the need for synchronization at creation.

EDIT ：添加关于C ++和静态变量的信息

EDIT: adding info about C++ and static variables

在C ++中，静态变量也在执行前初始化，如David Harkness for Java。在C ++中的一个问题可能是在嵌入式环境中，其中调用malloc / new不能执行，直到系统初始化，在这种情况下使用Singleton静态初始化器可能有问题。

In C++, static variables are also initialized before execution like David Harkness mentions for Java. One issue with this in C++ can be in embedded environments where calls to malloc/new cant be performed until after the system is initialized, in which case using a Singleton static initializer could be problematic.

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