throw（）在c ++异常结构中的函数声明之后？ [英] throw () after function declaration in c++ exception struct?

问题描述

以下是 http://www.tutorialspoint.com/cplusplus/cpp_exceptions_handling.htm

#include <iostream>
#include <exception>
using namespace std;

struct MyException : public exception
{
  const char * what () const throw ()
  {
    return "C++ Exception";
  }
};

我理解 const $ c> what 意味着该函数不会修改struct的任何
成员，但结尾处的 throw（） ？

I understand the const after what means the function does not modify any members of the struct, but what does the throw() at the end mean?

推荐答案

这意味着它不会抛出任何异常。这是一个重要的保证，例如 what ，通常在异常处理中调用：你不想要另一个异常抛出，而你试图处理一个。

It means it won't throw any exceptions. This is an important guarantee for a function like what, which is usually called in exception handling: you don't want another exception to be thrown while you're trying to handle one.

在C ++ 11中，通常应该使用 noexcept 。旧的投放规格已弃用。

In C++11, you generally should use noexcept instead. The old throw specification is deprecated.

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