为什么这不是一个POD类型？ [英] Why isn't this a POD type?

问题描述

我在g ++ 4.6.2（mingw）上使用 g ++ -std = c ++ 0x pod_test.cpp 运行下面的代码。我在A4上遇到错误。为什么不是A4 POD？

I ran the below with g++ -std=c++0x pod_test.cpp on g++ 4.6.2 (mingw). I get an error on A4. Why isn't A4 POD?

#include <iostream>
#include <new>
#include <cstring>

using namespace std;

struct A {
    int a, b;
    char c;
};
struct A2 {
    short buf[1];
};
struct A3:A {
};
struct A4:A {
    short buf[1];
};
static_assert(std::is_pod<A>::value, "Struct must be a POD type");
static_assert(std::is_pod<A2>::value, "Struct must be a POD type");
static_assert(std::is_pod<A3>::value, "Struct must be a POD type");
static_assert(std::is_pod<A4>::value, "Struct must be a POD type");

int main(){}

推荐答案

这不是POD，因为它打破了这个标准布局类的规则：

It's not POD because it breaks this rule for standard layout classes:

- 最多没有非静态数据成员派生类和
至多一个具有非静态数据成员的基类，或没有带非静态数据成员的
类

— either has no non-static data members in the most derived class and at most one base class with non-static data members, or has no base classes with non-static data members

继承网格中只有一个类可以具有非静态数据成员。在这种情况下，
A 和 A4 都有。

Only one class in the inheritance lattice can have non-static data members. In this case, both A and A4 have.

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