如何在C ++中将空格和换行符分隔的整数读取为2D数组？ [英] How to read space and newline separated integers into a 2D array in C++?

问题描述

我有一个由空格分隔的.txt文件（在这种情况下，所有小于100），用新行分隔的行。像这样：

I have a .txt file of numbers (in this case all less than 100) separated by spaces, in rows separated by new lines. Something like this:

 41 53 07 91 44
 52 17 13 03 21

我想读这些数字到一个2d数组，就像它们出现，使空格分隔数组的列，单独的行。

I would like to read these numbers into a 2d array, exactly as they appear, so that spaces separate columns of the array, and new lines separate rows.

我可以让它以字符串形式读取行，但是我无法分离出单个数字，并将其作为整数处理。 p>

I can get it to read the lines in as strings, but then I'm having trouble separating out individual numbers, and getting it to treat them as integers.

推荐答案

尝试：

#include <vector>
#include <string>
#include <fstream>
#include <sstream>
#include <iostream>

int main()
{
    // The result of the read is placed in here
    // In C++, we use a vector like an array but vectors can dynamically grow
    // as required when we get more data.
    std::vector<std::vector<int> >     data;

    // Replace 'Plop' with your file name.
    std::ifstream          file("Plop");

    std::string   line;
    // Read one line at a time into the variable line:
    while(std::getline(file, line))
    {
        std::vector<int>   lineData;
        std::stringstream  lineStream(line);

        int value;
        // Read an integer at a time from the line
        while(lineStream >> value)
        {
            // Add the integers from a line to a 1D array (vector)
            lineData.push_back(value);
        }
        // When all the integers have been read, add the 1D array
        // into a 2D array (as one line in the 2D array)
        data.push_back(lineData);
    }
}

这篇关于如何在C ++中将空格和换行符分隔的整数读取为2D数组？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！