错误C2440：'='：无法从'const char [2]'转换为'char' [英] error C2440: '=' : cannot convert from 'const char [2]' to 'char'

问题描述

我正在学习c ++，我在做一些新手事情时遇到问题。我试图创建一个非常小的应用程序，它接受用户输入并将其存储到一个字符数组。然后我解析通过该数组，删除所有括号和dases并显示它。例如以下

I am learning c++, and I am having issues doing some newbie things. I am trying to create a very small application that takes the users input and stores it into a char array. I then parse through that array and remove all parenthesis and dases and display it. like the following

[phone]
to

3258587455

[phone] to
3258587455

但我遇到错误

 error C2440: '=' : cannot convert from 'const char [2]' to 'char'

下面是我的简单代码，可以轻松地在编译器中抛出并运行。

Below is my simple code that can easily be thrown in a compiler and ran.

#include "stdafx.h"
#include<iostream>
#include<conio.h>

using namespace std;

/*
This is a template Project
*/
int main()
{
    char phoneNum[25];

    for(int i = 0; i < (sizeof(phoneNum) / sizeof(char)); i++)
    {
        phoneNum[i] = "i";
    }


    cout<< "Enter a phone Number" <<endl;
    cin>>phoneNum;

    if(phoneNum[0] != '(' || phoneNum[4] != ')' || phoneNum[8] != '-')
    {
        cout<<"error";
    }
    else
    {

        for(int i = 0; i < (sizeof(phoneNum) / sizeof(char));i++)
        {
            if(phoneNum[i] != '(' || phoneNum[i] != ')' || phoneNum[i] != '-')
            {
                cout<<phoneNum[i];
            }
        }
    }

    cin>>phoneNum;
    getchar();


    return 0;
}

它没有完全完成，所以如果任何人有任何指针，从字符串中删除字符串字符。那太好了。

It is not completely finished so if anyone has any pointers on the best way to remove strings characters from a string. that would be great.

推荐答案

问题在这里，我相信：

phoneNum[i] = "i";

您要分配一个字符，所以您需要使用单

You want to assign a single character, so you need to use single quotes for your literal:

phoneNum[i] = 'i';

可能还有其他问题 - 我只试图修复标题中提到的问题： ）

There may well be other problems - I've only tried to fix the one mentioned in the title :)

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