在C ++中解析命令行参数有什么有效的方法？ [英] What's an effective way to parse command line parameters in C++?

问题描述

有没有一个真正有效的方式来处理C ++中的命令行参数？

我在下面做什么感觉完全业余，我不能想象这是在专业软件中真正处理命令行参数（atoi，硬编码argc检查）。

 
 //命令行用法：sum num1 num2 
 
 int main（int argc，char * argv []）
 {
    if（argc< 3）
&    {
       cout<< 用法：< argv [0]<< num1 num2 \\\
; 
       exit（1）; 
   } 
 
    int a = atoi（argv [1]）; 
    int b = atoi（argv [2]）; 
    int sum = a + b; 
 
    cout< Sum：< sum< \\\
; 
 
    return 0; 
} 
 
 
 
解决方案
您可能想使用外部库。有很多可供选择。
 
 
 
 Boost具有非常丰富的功能（像往常一样）库加入计划选项。
 
 
 
我最后的个人最爱几年来一直是 TCLAP   - 纯粹模板化，因此没有库或链接，自动化帮助代和其他好东西。请参阅文档中的最简单的示例。
 
Is there a really effective way of dealing with command line parameters in C++?

What I'm doing below feels completely amateurish, and I can't imagine this is how command line parameters are really handled (atoi, hard-coded argc checks) in professional software.
// Command line usage: sum num1 num2

int main(int argc, char *argv[])
{
   if (argc < 3)
   {
      cout << "Usage: " << argv[0] << " num1 num2\n";
      exit(1);
   }

   int a = atoi(argv[1]);
   int b = atoi(argv[2]);
   int sum = a + b;

   cout << "Sum: " << sum << "\n";

   return 0;
}

解决方案
You probably want to use an external library for that.  There are many to chose from.

Boost has a very feature-rich (as usual) library Boost Program Options.

My personal favorite for the last few years has been TCLAP -- purely templated, hence no library or linking, automated '--help' generation and other goodies. See the simplest example from the docs.

                        
这篇关于在C ++中解析命令行参数有什么有效的方法？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！