虚函数在派生类中声明为非虚函数 [英] virtual function declared non-virtual in a derived class

问题描述

如果一个函数在派生类中声明为非虚函数，当基类的函数是virutal，为什么它调用一个vtable查找调用函数的指针？

If a function is declared non-virtual in a derived class when the base class function was virutal, why does it invoke a vtable lookup on calling the function on its pointer? The function is clear from the scope.

推荐答案

在C ++中，如果你声明一个方法 virtual 在基类中，那么它的虚拟也在派生类中，即使 virtual 关键字被省略。

In C++ if you declare a method virtual in the base class then it's virtual also in derived class, even if the virtual keyword is omitted.

为了文档的目的，但在我看来很好，无论如何重复。

For documentation purposes is however in my opinion nice to repeat it anyway.

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