可以重新排序函数调用 [英] Can function calls be reordered

问题描述

我使用C ++ 98。函数调用在什么程度上可以重新排序？我不使用任何全局状态，只有状态对象的本地函数。

I am using C++98. To what extent can function calls be reordered? I am not using any global state, only state of objects local to the function.

我的具体情况是：

{
  RaiiType T;
  Object1.FunctionCall();
  Object2.FunctionCall();
}

其中Object1和Object2在下一个范围中声明。是允许 T 的构造函数在函数调用之后重新排序，假设它可以被简单地证明（至少对于人类），在构造和函数调用？

Where Object1 and Object2 are declared in the next scope up. Is the constructor for T permitted to be reordered after either function call, assuming that it can be trivially proven (at least to a human) that there are no dependencies between the construction and the function calls?

在我特定的情况下，RAII对象用于计算函数调用的执行时间。 / p>

In my particular case, the RAII object is used to time the execution of the function calls.

推荐答案

只要符合标准的程序无法区分其

So long as a standards-compliant program could not tell the difference in its observable behavior, the compiler (as well as other components in the system) may freely reorder instructions and operations however it likes.

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