C ++检查数组中是否存在元素 [英] C++ check if element exists in array

问题描述

我发现了很多这样的话题，但对我来说太复杂了。

I've found a lot of topics like this, but it was kinda too complicated for me.

如何检查数组中是否存在元素？

How to check if element exists in an array?

首先声明一个数组，

for(int l=0;l<=21;l++){
        skirt[l]=l;
    }

c>我想检查其他数组中存在的任何元素是否在数组 skirt [];

and then with another for I'd like to check if any element which exist in other array is in array skirt[];

for(int k=0;k<=n;k++){
    if(skaiciai[k]!=skirt[k]){
        counter++;
    }
}

推荐答案

循环：

for(int k=0;k<=n;k++){
    if(skaiciai[k]!=skirt[k]){
        counter++;
    }
}

只会比较数组中相同索引处的元素。嵌套用于循环，外部用于循环遍历一个数组中的元素，内部 for 循环遍历其他数组中的元素：

would only compare elements at the same index in the arrays. Nested for loops are required with the outer for loop iterating over the elements in one array and the inner for loop iterating over elements in the other array:

for (int k_skirt = 0; k_skirt <= n; k_skirt++)
{
    for (int k_skaiciai = 0; k_skaiciai <= n; k_skaiciai++)
    {
        if(skaiciai[k_skaicia] == skirt[k_skirt]){
            counter++;
        }
    }
}

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