写入桶排序在c ++ [英] Writing bucket sort in c++

问题描述

一本书我说：

a）根据值的个位数将一维数组的每个值放入桶数组的一行。例如，97被放置在行7中，3被放置在行3中，并且100被放置在行0中。这被称为分配通行证。

a) Place each value of the one-dimensional array into a row of the bucket array based on the value's ones digit. For example, 97 is placed in row 7, 3 is placed in row 3, and 100 is placed in row 0. This is called a "distribution pass."

b ）逐行循环通过桶阵列，并将值复制回原始数组。这被称为收集通行证。一维数组中上述值的新顺序为100,3和97.

b) Loop through the bucket array row by row, and copy the values back to the original array. This is called a "gathering pass." The new order of the preceding values in the one-dimensional array is 100, 3, and 97.

c）对每个后续数字位置重复此过程。

c) Repeat this process for each subsequent digit position.

我有很多麻烦试图理解和实现这个。到目前为止我有：

I am having a lot of trouble trying to understand and implement this. So far I have:

void b_sort(int sarray[], int array_size) {
    const int max = array_size;
    for(int i = 0; i < max; ++i)
        int array[i] = sarray[i];

    int bucket[10][max - 1];
}

我想是为了排序他们， ，etc，我可以使用这个：

I'm thinking that in order to sort them by ones, tens, hundreds, etc, I can use this:

for(int i = 0; i < max; ++i)
    insert = (array[i] / x) % 10;
    bucket[insert];

其中x = 1,10,100,1000等我完全失去了如何写

where x = 1, 10, 100, 1000, etc. I am totally lost on how to write this now.

推荐答案

这里是根据OP问题中的信息进行桶排序。

Here's a bucket sort based on the info in the OP question.

void b_sort(int sarray[], int array_size) {
    const int max = array_size;
    // use bucket[x][max] to hold the current count
    int bucket[10][max+1];
    // init bucket counters
    for(var x=0;x<10;x++) bucket[x][max] = 0;
    // main loop for each digit position
    for(int digit = 1; digit <= 1000000000; digit *= 10) {
        // array to bucket
        for(int i = 0; i < max; i++) {
            // get the digit 0-9
            int dig = (sarray[i] / digit) % 10;
            // add to bucket and increment count
            bucket[dig][bucket[dig][max]++] = sarray[i];
        }
        // bucket to array
        int idx = 0;
        for(var x = 0; x < 10; x++) {
            for(var y = 0; y < bucket[x][max]; y++) {
                sarray[idx++] = bucket[x][y];
            }
            // reset the internal bucket counters
            bucket[x][max] = 0;
        }
    }
}

strong>对于bucket使用2d数组会浪费很多空间...一个队列/列表数组通常更有意义。

Notes Using a 2d array for the bucket wastes a lot of space... an array of queues/lists usually makes more sense.

我通常不编程C ++和上面的代码是写在web浏览器中，所以语法错误可能存在。

I don't normally program in C++ and the above code was written inside the web browser, so syntax errors may exist.

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