给定2个16位整数，我可以交织这些位形成一个单一的32位int？ [英] Given 2 16-bit ints, can I interleave those bits to form a single 32 bit int?

问题描述

这是什么正确的方法？假设我有ABCD和abcd，输出位应该是像AaBbCcDd。

Whats the proper way about going about this? Lets say I have ABCD and abcd and the output bits should be something like AaBbCcDd.

unsigned int JoinBits(unsigned short a, unsigned short b) { }

推荐答案

#include <stdint.h>

uint32_t JoinBits(uint16_t a, uint16_t b) {
  uint32_t result = 0;
  for(int8_t ii = 15; ii >= 0; ii--){
    result |= (a >> ii) & 1;
    result <<= 1;
    result |= (b >> ii) & 1;
    if(ii != 0){
      result <<= 1;
    }
  }
  return result;
}

也在ideone上进行测试： http://ideone.com/lXTqB 。

also tested on ideone here: http://ideone.com/lXTqB.

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