如何一个子类调用超类的方法与子类的相同的方法名称？ [英] How can a subclass call a method of the superclass with the same method name of the subclass?

问题描述

#include <iostream>
using namespace std;

class Person {
public:
    void sing();
};

class Child : public Person {
public:
    void sing();
};

Person::sing() {
    cout << "Raindrops keep falling on my head..." << endl;
}

Child::sing() {
    cout << "London bridge is falling down..." << endl;
}

int main() {
    Child suzie;
    suzie.sing(); // I want to know how I can call the Person's method of sing here!

    return 0;
}

推荐答案

suzie.Person::sing();

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