XLib窗口名称问题 [英] XLib Window Name Problems

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本文介绍了XLib窗口名称问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

从4天,我试图看看XLib如何工作,我终于明白了。
我试图做一个简短的程序,检索打开的窗口的名称。
为此,我创建了两个函数:

since 4 days, I try to see how XLib works, and I have finally understood that. Si I tried to make a short program wich retrieve open window's name. For that, I created 2 functions :

Window *list (Display *disp, unsigned long *len) {
    Atom prop = XInternAtom(disp,"_NET_CLIENT_LIST",False), type;
    int form;
    unsigned long remain;
    unsigned char *list;

    if (XGetWindowProperty(disp,XDefaultRootWindow(disp),prop,0,1024,False,XA_WINDOW,
                &type,&form,len,&remain,&list) != Success) {
        return 0;
    }

    return (Window*)list;
}

所以,这个第一个函数返回所有窗口的窗口对象。
然后,我创建了一个函数来从所有这些窗口中检索名称。

So, this first function return a window object of all the windows. Then, I created a function to retrieve the name from all those windows.

char *name (Display *disp, Window win) {
    Atom prop = XInternAtom(disp,"WM_NAME",False), type;
    int form;
    unsigned long remain, len;
    unsigned char *list;


    if (XGetWindowProperty(disp,win,prop,0,1024,False,XA_STRING,
                &type,&form,&len,&remain,&list) != Success) {

        return NULL;
    }

    return (char*)list;
}

这个函数很好,main.c示例:

And this function works fine, an main.c example:

int main(int argc, char* argv[]){
    int i;
    unsigned long len;
    XKeyEvent esend;
    Display *disp = XOpenDisplay(NULL);
    Window *list;
    char *name;

        list = (Window*)list(disp,&len);
    for (i=0;i<(int)len;i++) {
        name = name(disp,list[i]);
        printf("%d :  %s \n",i,name);
        free(name);
        }
}

它返回:

1:Xlib编程手册:键盘和指针事件 - Google Chrome

1 : Xlib Programming Manual: Keyboard and Pointer Events - Google Chrome

2:Debian Web [En fonction] - Oracle VM VirtualBox

2 : Debian Web [En fonction] - Oracle VM VirtualBox

3:XChat:necromoine @ /(+ CSTfnst 10:2)

3 : XChat: necromoine @ / (+CSTfnst 10:2)

4:

5:root @ root-Laptop:〜

5 : root@root-Laptop: ~

6:

并且,数字4和6是空白的(我实际上有两个打开的skype窗口)。

And, the number 4 and 6 are blank (I actually have two opened skype window).

你能帮我。

推荐答案

A WM_NAME 不一定是简单的字符串。它可以是复合文本(不同类型的字符串),实际上是Skype窗口的情况。您需要使用 AnyPropertyType 而不是 XA_STRING 获取属性,然后根据实际类型进行格式化。看看 xprops 的来源,看看是怎么做的。

A WM_NAME is not necessarily a simple string. It could be a compound text (a different type of string), which is actually the case for Skype windows. You need to use AnyPropertyType instead of XA_STRING to get the property, then format according to actual type. Look at the source of xprops to see how it's done.

这篇关于XLib窗口名称问题的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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