模板类型检查C ++ [英] Template type check C++

问题描述

我有一个接受对象的模板函数。我需要确定对象是否派生自特定的基类。如果它是从基类派生的，我需要调用额外的函数。有没有我可以在C + + Linux？

I have a template function which takes in objects. I need to determine whether the object is derived from a particular base class. If it is derived from the base class, I need to call additional function. Is there anyway I could do it in C++ Linux?

class baseA{
};

class derivedA:baseA{

};

class testB{
};

template<typename T>
void functionA(const T& value){

//if T is derived from baseA, call an additional function

//perform common operations for derivedA and testB...

}

derivedA中的成员函数，但不在testB中。

To clarify, the additional function is a member function in derivedA but not in testB.

推荐答案

Boost.TypeTraits
boost :: is_base_of

Boost.TypeTraits boost::is_base_of

const bool is = boost::is_base_of<Base,Derived>::value;

is_base_of如何工作？

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