Access成员字段与本地变量（或参数）具有相同的名称 [英] Access member field with same name as local variable (or argument)

问题描述

请考虑以下代码段：

  struct S 
 {
 S（const int a）
 {
 this-> a = a; // option 1 
 S :: a = a; // option 2 
} 
 int a; 
}; 
  

选项1相当于选项2？有一种形式比另一种形式更好的情况吗？选项1相当于选项2，但是选项1不适用于静态的选项2。数据成员

EDITED：可以使用此指针访问静态数据成员。但是this->成员不会在静态函数中工作。但选项2将在静态函数中使用静态成员。

例如：

  struct S 
 {
 static void initialize（int a）
 {
 // this-> a = a;编译错误
 S :: a = a; 
} 
 static int a; 
}; 
 int S :: a = 0; 
  

Consider following code snippet:

struct S
{
   S( const int a ) 
   { 
      this->a = a; // option 1
      S::a = a; // option 2
   }
   int a;
};

Is option 1 is equivalent to option 2? Are there cases when one form is better than another? Which clause of standard describes these options?

解决方案

option 1 is equivalent to option 2, but option 1 will not work for a static data member

EDITED: static data members can be accessed with this pointer. But this->member will not work in static function. but option 2 will work in static function with static member

Eg:

struct S
{
   static void initialize(int a)
   {
      //this->a=a; compilation error
      S::a=a; 
   }
   static int a;
};
int S::a=0;

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