什么语法::〜意味着在C + + Visual Studio 2010新添加的类 [英] What exactly does the syntax ::~ mean in newly added class in C++ Visual Studio 2010

问题描述

我有一个简单的问题：

情况：
当我右击Source Files文件夹并选择Add-> Class - C ++类，
a类被添加到一个单独的文件* .cpp和* .h（伟大！这正是我想要的）。

现在：函数名称

  classname ::〜classname（void）
  

究竟是什么？

是类名为classname的析构函数吗？

我在互联网上找不到这个语法::〜的解释，所以我在这里问。 ：）

解决方案

这里有两种不同的工作方式：

• 命名空间定界符运算符 ::


• 析构函数，它是一个特殊函数 在您的情况下，语法 classname ::〜classname（void）只是定义类的析构函数。 :: 意味着以下属于 classname 的类。接下来的只是析构函数名（参见上文）。
  
  
  

  这是与所有类成员定义相同的语法。如果你的类有一个名为 foo 的函数，它接受一个 int ，并返回一个 int ，那么它在类外的定义如下：

    int classname :: foo b $ b  

  这与destructor完全相同（除了析构函数没有返回值， ）。

  
  

  I have s simple question:

  Situation: When I rightclick Source Files folder and select Add->Class - C++ class , a class is added in a separate file *.cpp and *.h (great! This is exactly what I wanted).

  Now: what does the function name

  classname::~classname(void)
  

  exactly does ?

  Is it a destructor of that class called "classname" ?

  I cannot find explanation of this syntax "::~" on the internet, and so I am asking here. :)

  解决方案

  There are two different things at work here:

  • The namespace delimiter operator, ::
  • The destructor, which is a special function that’s always called ~classname.

  In your case, the syntax classname::~classname(void) simply defines the class’ destructor. The :: means that what follows belongs to the class called classname. And what follows is just the destructor name (see above).

  This is the same syntax used for all class member definitions. If your class had a function called foo that took an int and returned an int, then its definition outside the class would look as follows:

  int classname::foo(int)
  

  This is exactly the same as with the destructor (except that the destructor has no return value and takes no arguments).

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