为什么“pragma GCC诊断推送”在GCC / C ++中弹出警告？ [英] Why "pragma GCC diagnostic push" pop warning in GCC/C++?

问题描述

  #pragma GCC diagnostic push 
 
 it pop：warning：expected [error | warning | ignored] code> 

为什么？我在Linux中使用GCC。

我有一个问题，如果我不能使用pop / push，如果忽略 only cpp，不影响其他cpp？

#pragma GCC诊断推送

c $ c>和 #pragma GCC诊断流行音乐是新增的gcc 4.6 。您使用的是旧版本。

这些编译指示通常与其他#pragma GCC diagnostic 指令，以抑制，打开或转换为代码的一小部分的特定错误警告只要。如果它们被忽略，对警告级别的更改将应用​​于源文件的其余部分，而不是直到下一个 #pragma GCC诊断pop 。这可能不是一个问题，或者它可能是世界的尽头;您需要了解您的代码，以确定是否知道。

无论如何，你应该更新你的编译器。你不会用C89编译器编译C99;不要使用gcc 4.4编译包含gcc 4.6的编译指令的代码。

#pragma GCC diagnostic push

it pop: warning: expected [error|warning|ignored] after â#pragma GCC diagnosticâ

Why? I use GCC in Linux.

I have one question, if I can't use pop/push, if the ignore only influence the compiled cpp, not influence other cpp? if some other include the cap, if influence it?

解决方案

#pragma GCC diagnostic push and #pragma GCC diagnostic pop were added in gcc 4.6. You're using an older version.

These pragmas are typically used in conjunction with other #pragma GCC diagnostic directives to suppress, turn on, or turn into an error specific warnings for a small section of your code only. If they're ignored, the changes to warning levels will apply to the rest of the source file rather than just until the next #pragma GCC diagnostic pop. This may not be a problem, or it may be the end of the world; you'll need to understand your code to know for sure.

Either way, you should probably update your compiler. You wouldn't compile C99 with a C89 compiler; don't compile code containing pragmas for gcc 4.6 with gcc 4.4.

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