将time_t转换为int [英] Converting time_t to int

问题描述

我想将给定时间转换成epoch（time_t），反之亦然。

更新

  epoch_strt.tm_sec = 0; 
 epoch_strt.tm_min = 0; 
 epoch_strt.tm_hour = 0; 
 epoch_strt.tm_mday = 1; 
 epoch_strt.tm_mon = 1; 
 epoch_strt.tm_year = 70; 
 epoch_strt.tm_isdst = -1; 
 
 double nsecs = difftime（curtime，basetime）; //系统当前时间，我将其转换为struct tm 
  

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解决方案

您应该将其转换为 long int 而不是 int 。

  long int t = static_cast< long int> time（NULL）; 
  

int 可能不足例如，在我的平台上， time_t 是 typedef 的 __ int64 。

I want to convert a given time into epoch(time_t) and vice versa. can anyone tell what is the routine or algorithm for this?

Thanks

Update

 epoch_strt.tm_sec = 0;
 epoch_strt.tm_min = 0;
 epoch_strt.tm_hour = 0;
epoch_strt.tm_mday = 1;
epoch_strt.tm_mon = 1;
epoch_strt.tm_year = 70;
 epoch_strt.tm_isdst = -1;

double nsecs = difftime(curtime, basetime);//current time from system, I converrting it to struct tm

but this always return 32399 for some reason.

解决方案

You should cast it to a long int instead of int.

long int t = static_cast<long int> time(NULL);

An int might not be enough to hold the time, for example, on my platform, time_t is a typedef of __int64.

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