不命名A在C ++中键入 [英] Does Not Name A Type in C++

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本文介绍了不命名A在C ++中键入的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在C ++当我得到一个错误,说xxxxx不命名一个类型在yyy.h



这是什么意思?



yyy.h 包含 xxxx 的标头。



例如,我使用:

  typedef CP_M_ReferenceCounted FxRC; 

,我已将 CP_M_ReferenceCounted.h yyy.h



我缺少一些基本的理解,是什么?

解决方案

这似乎需要相应地引用命名空间。例如,下面的yyy.h和test.cpp与你的问题相同:

  // yyy.h 
#ifndef YYY_H__
#define YYY_H__

命名空间Yyy {

class CP_M_ReferenceCounted
{
}

}

#endif

//test.cpp
#includeyyy.h
$ b b typedef CP_M_ReferenceCounted FxRC;


int main(int argc,char ** argv)
{

return 0;
}

错误是

  ...错误:CP_M_ReferenceCounted未命名类型

但添加一行using namespace Yyy;解决了以下问题:

  // test.cpp 
#includeyyy.h
// add this line
using namespace Yyy;

typedef CP_M_ReferenceCounted FxRC;
...

因此,请检查.h头文件中的命名空间范围。 p>

in C++ when i get an error that says xxxxx does not name a type in yyy.h

What does that mean?

yyy.h has included the header that xxxx is in.

Example, I use:

typedef CP_M_ReferenceCounted FxRC;

and I have included CP_M_ReferenceCounted.h in yyy.h

I am missing some basic understanding, what is it?

解决方案

That seems you need to referring the namespace accordingly. For example, following yyy.h and test.cpp have the same problem as yours:

//yyy.h
#ifndef YYY_H__
#define YYY_H__

namespace Yyy {

class CP_M_ReferenceCounted
{
};

}

#endif

//test.cpp
#include "yyy.h"

typedef CP_M_ReferenceCounted FxRC;


int main(int argc, char **argv)
{

        return 0;
}

The error would be

...error: CP_M_ReferenceCounted does not name a type

But add a line "using namespace Yyy;" fixs the problem as below:

//test.cpp
#include "yyy.h"
// add this line
using namespace Yyy;

typedef CP_M_ReferenceCounted FxRC;
...

So please check the namespace scope in your .h headers.

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