我继承了一个使用私有的构造函数，为什么我仍然能够从主函数访问它？ [英] I Inherited a constructor using private, Why am I still be able to access it from main function?

问题描述

#include <iostream>
using namespace std;

class base{
public:
    int i;
    base(){
    i=1;
    cout<<"Base Constructor";
    }
};

class derived: private base{
    public:
    derived(){
    i=2;
    cout<<"Derived constructor";
    }
};


int main(){ 
derived c;
return 0;
}

对于上面的代码，我得到的输出为
基础构造函数构造函数
即使我继承使用私有吗？

For the above code why am I getting the output as "Base ConstructorDerived Constructor" even though I inherited using private?

推荐答案

为什么我仍然可以从主函数访问它？

Why am I still be able to access it from main function?

您不是。

您的主函数访问 / code>的构造函数，它可以访问。

Your main function accesses derived's constructor, which it has access to.

和 base 的建构函式， 可存取。

And derived's constructor accesses base's constructor, which it has access to.

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