在C ++中转换为大写 [英] Converting to uppercase in C++

问题描述

假设您有：

  const char * something =m 
 

如何使用toupper（或其他东西，如果适用）使这个大写？

我想使用 char * 而不是 string 我可以使用一个字符串，但是我必须使用 str.c_str（））。

我可以让 char * something =m; 包含M？

一个字符串文字（ char * something ）。尝试数组：

  char something [] =m 
 something [0] = toupper（something [0]）; 
  

要更改整个字符串：

  char something [] =hello; 
 char * p = something; 
 
 while（* p）{
 * p = toupper（* p）; 
 p ++; 
} 
  




Let's say you have:

const char * something = "m";

How would one make this uppercase, using toupper (or something else, if applicable)?

I want to use a char * instead of a string (I can use a string, but then I have to use str.c_str()).

So, how can I make char * something = "m"; contain "M"?

解决方案

I find you choice of C strings disturbing.. but anyway.

You can't change a string literal (char *something). Try an array:

char something[] = "m";
something[0] = toupper(something[0]);

To change an entire string:

char something[] = "hello";
char *p = something;

while (*p) {
    *p = toupper(*p);
    p++;
}

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