在嵌套模板专门化期间初始化嵌套模板类的静态成员？ [英] Initializing static member of nested templated class during nested template specialization?

问题描述

这里是我的问题：

template<typename T>
class Outer 
{
public:
    template<typename U>
    class Inner 
    {
    private:
        static int count;
    };

    static int code;
    void print() const
    {
        std::cout << "generic";
    }
};

template<>
template<>
class Outer<bool>::Inner<bool> 
{
    static int count;
};

template<>
template<>
int Outer<bool>::Inner<bool>::count = 4; // ERROR

如何正确初始化？

推荐答案

完全专用的模板实际上不再是模板，因此您的定义应该是：

Fully-specialized templates are in fact no longer templates, so your definition should simply be:

int Outer<bool>::Inner<bool>::count = 4;

完全使用所有定义后，代码应如下所示：

In full, with all definitions in place, your code should look like:

template<typename T>
class Outer 
{
public:
    template<typename U>
    class Inner 
    {
    private:
        static int count;
    };

    static int code;
    void print() const
    {
        std::cout << "generic";
    }
};

template<typename T>
int Outer<T>::code = 0;

template<typename T>
template<typename U>
int Outer<T>::Inner<U>::count = 0;

template<>
template<>
class Outer<bool>::Inner<bool> 
{
    static int count;
};

int Outer<bool>::Inner<bool>::count = 4;

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