操作符在C ++中重载“+”运算符 [英] Operator overloading '+' operator in C++
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问题描述
我在下面的代码中遇到问题,该代码在Visual Studio 2008上运行。当您有如下的重载语句时,如何为 operator +
编写函数定义?
I am facing a problem with the code below which is run on Visual Studio 2008. How do I write the function definition for operator +
when you have a statement to be overloaded as follows?
class Distance
{
private:
int feet,inches;
};
main......
Distance Obj, Obj1(2, 2);
Obj = 3 + Obj1; // This line here
Obj1 + 3
假设我必须将值3添加到数据成员 c>
Suppose I have to add the value 3 to the data member feet
of Obj1
.
推荐答案
该表单的运算符将声明为:
Generally an operator of that form would be declared as:
Distance operator+(int lhs, const Distance& rhs) {
// Assuming the int value represents feet
return Distance(rhs.feet + lhs, rhs.inches);
}
您可能还想定义对称:
Distance operator+(const Distance& lhs, int rhs) {
// Assuming the int value represents feet
return Distance(lhs.feet + rhs, lhs.inches);
}
此外,我建议你听从詹姆斯·麦克内利斯的意见 - 你的工作如果您只有一个成员在一个单元中表示长度,则可以简化。
Also, I suggest you heed the advice of James McNellis--your job will be simplified if you just have one member representing lengths in a single unit.
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