强制返回的对象被赋值 [英] force returned object to be assigned

问题描述

是否有一种方法，在C ++中，强制分配函数的返回值？
ie如果我有一个成员函数foo

  class myClass {
 ... 
 public：
 T1 foo（T2 x）{T1 y; / * something * / return y;}; 
} 
  

我可以在main（）中调用

  myClass obj; 
 T1 a = obj.foo（x）; //<  -  
  

我可以进行更简单的调用

  myClass obj; 
 obj.foo（x）; // < -  
  

（不存储返回的值） / p>

或者，我可以区分

的定义

  T1 a = obj .foo（x）; 
 obj.foo（x）; 
  
 
 
 
感谢您的时间，对不起我的无知。
解决方案
不，没有办法强制对返回的对象进行操作。
 
 
 
区分
  T1 a = obj.foo（x）; 
 obj.foo（x）; 
  
（至少不是以可移植的标准方式。堆栈等，但你为什么）。
 
is there a way, in C++, to force the assignation of the returned value of a function? 
i.e. if I have a member function foo 
class myClass{
    ...
    public:
    T1 foo(T2 x){T1 y; /*something*/ return y;};
}
which I can call in the main() as
myClass obj;
T1 a = obj.foo(x);  //<--
can I make the simpler call 
myClass obj;
obj.foo(x);   //<--
(that does not store the returned value) somehow "illegal"?

Alternatively, can I distinguish the definitions of
T1 a = obj.foo(x);
obj.foo(x);
thank you for your time and sorry for my ignorance
解决方案
No, there's no way to force an operation on a returned object.

And no, you can't distinguish between
T1 a = obj.foo(x);
obj.foo(x);
inside the calls (at least not in a portable, standard way. You could hack away with call-stacks and such, but why would you).

                        
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