在c ++中将字符串转换为argv [英] convert string to argv in c++

问题描述

我有一个std ::字符串包含一个要执行execv的命令，什么是最好的C ++方式将其转换为execv（）的第二个参数所需的char * argv []

I have an std::string containing a command to be executed with execv, what is the best "C++" way to convert it to the "char *argv[]" that is required by the second parameter of execv()?

澄清：

std::string cmd = "mycommand arg1 arg2";
char *cmd_argv[];

StrToArgv(cmd, cmd_argv); // how do I write this function?

execv(cmd_argv[0], cmd_argv);

推荐答案

std::vector<char *> args;
std::istringstream iss(cmd);

std::string token;
while(iss >> token) {
  char *arg = new char[token.size() + 1];
  copy(token.begin(), token.end(), arg);
  arg[token.size()] = '\0';
  args.push_back(arg);
}
args.push_back(0);

// now exec with &args[0], and then:

for(size_t i = 0; i < args.size(); i++)
  delete[] args[i];

当然，这不适用于使用 rm file.mp3。你可以考虑POSIX函数 wordexp ，它关心这些和更多。

Of course, this won't work with commans that use quoting like rm "a file.mp3". You can consider the POSIX function wordexp which cares about that and much more.

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