自定义字节大小？ [英] Custom byte size?

问题描述

所以，你知道char类型的原语的大小是1字节吗？我如何使自定义大小的原始？所以喜欢而不是一个int的大小为4字节我使一个大小的让我说16.
有没有办法做到这一点？有没有办法？

So, you know how the primitive of type char has the size of 1 byte? How would I make a primitive with a custom size? So like instead of an in int with the size of 4 bytes I make one with size of lets say 16. Is there a way to do this? Is there a way around it?

推荐答案

通常你只需要创建一个表示你感兴趣的数据的结构。如果它是16个字节的数据，它是一些较小类型的聚合，或者你正在使用一个本地的16字节整数类型的处理器。

Normally you'd just make a struct that represents the data in which you're interested. If it's 16 bytes of data, either it's an aggregate of a number of smaller types or you're working on a processor that has a native 16-byte integral type.

如果您想要表示非常大的数字，您可能需要找到一个处理任意大小的数字的特殊库。

If you're trying to represent extremely large numbers, you may need to find a special library that handles arbitrarily-sized numbers.

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