程序跳过一行代码 [英] program skipping a line of code

问题描述

我一直在这个程序工作了一段时间，我终于摆脱了编译错误。但是当我尝试时，程序基本上跳过了一行代码。

I have been working on this program for a while and I finally got rid of the compile errors. But when I tried it, the program basically skipped a line of code.

#include <iostream>
#include <cstdlib>
#include <cstring>
using namespace std;
int main(){
  string nameOfFile = "";
  char index;
  char title[100];
  char name[100];
  char copyright[100];

  cout << "Welcome, and hello to the html templating software" << endl;
  cout << "Is this your index page?\ny/n" << endl;

  cin >> index;
  if (index=='n'){
    cout << "Enter the prefered name of this file" << endl;
    getline(cin, nameOfFile, '\n');
  }

  cout << "What will the title of the page be?" << endl;
  cin.getline(title, 100);

  cout << "What is your name?" << endl;
  cin.getline(name, 100);

  cout << "What is the copyright?" << endl;
  cin.getline(copyright, 100);

  cin.get();
  return 0;
}

你看到如何在询问这是你的索引页后，跳过下一个<

You see how after asking if this is your index page it skips the next cin.getline function no matter the scenario.

推荐答案

当用户输入时，输入code> cin.getline 索引，他们也键入换行符，但您的cin没有从输入流中删除它。因此，您对cin.getline的调用将因为剩余的换行符而立即返回。

When the user entered the index, they also typed a newline, but your cin didn't remove it from the input stream. So, your call to cin.getline returns immediately because of the leftover newline.

添加对 cin.ignore 之前，cin.getline将其刷新。

Add a call to cin.ignore before the cin.getline to flush it out.

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