为什么此代码会给出错误，“template specialization requires”template<>'“？ [英] Why does this code give the error, "template specialization requires 'template<>'"?

问题描述

当我尝试使用Clang编译时

  template< class T& 
 struct字段
 {
 char const * name; 
 Field（char const * name）：name（name）{} 
}; 
 
 template< class Derived> 
 class CRTP {static Field< Derived> const _field; }; 
 
 class Class：public CRTP< Class> {}; 
字段< Class> const CRTP< Class> :: _ field（blah）; 
 
 int main（）{} 
  

我得到

 错误：模板专门化需要'template'>'
字段< Class> const CRTP< Class> :: _ field（blah）; 
 ~~~~~~~~~~~~ ^ 
  

的错误。我的 _field 定义有什么问题，我该如何解决？

code> _field 对于所有子类不一定相同。）

解决方案

编译器将此标识为模板专用化（例如，为了能够检查语法），需要模板关键字：

 模板<> 
字段< Class> const CRTP< Class> :: _ field（blah）; 
 

它的括号是空的，因为所有的模板参数是专门的，但你不能把它留下来。 p>


When I try to compile this with Clang

template<class T>
struct Field
{
    char const *name;
    Field(char const *name) : name(name) { }
};

template<class Derived>
class CRTP { static Field<Derived> const _field; };

class Class : public CRTP<Class> { };
Field<Class>   const CRTP<Class>::_field("blah");

int main() { }

I get

error: template specialization requires 'template<>'
Field<Class>   const CRTP<Class>::_field("blah");
                     ~~~~~~~~~~~  ^

I don't understand the error at all. What is wrong with my definition of _field and how do I fix it?

(Note that the arguments to _field are not necessarily the same for all subclasses.)

解决方案

For the compiler to identify this as a template specialization (e.g. to be able to check the syntax), you need the template keyword:

template<>
Field<Class> const CRTP<Class>::_field("blah");

Its brackets are empty as all template parameters are specialized, but you cannot just leave it away.

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