在C ++中将函数模板作为参数传递 [英] Pass a function template as a parameter in C++

问题描述

例如，我想从两个序列中获取最大值的列表， left 和 right ，将结果保存在之前定义和分配的 max_seq 中。

For example, I want to get a list of maximum values from two sequences, left and right, and save the results in max_seq, which are all previously defined and allocated,

std::transform(left.begin(), left.end(), right.begin(), max_seq.begin(), &max<int>);

但这不会编译，因为编译器说

But this won't compile because the compiler says

 note:   template argument deduction/substitution failed

我知道我可以在 struct 里面或者在 lambda 里面封装std :: max。但是有没有办法直接使用 std :: max 没有包装器？

I know I can wrapper "std::max" inside a struct or inside a lambda. But is there a way directly use std::max without wrappers?

推荐答案

std :: max 有多个重载，因此编译器无法确定要调用哪个。

std::max has multiple overloads, so the compiler is unable to determine which one you want to call. Use static_cast to disambiguate and your code will compile.

static_cast<int const&(*)(int const&, int const&)>(std::max)

[](int a, int b){ return std::max(a, b); }

现场演示

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