c ++向前声明一个静态类成员 [英] c++ forward declaration of a static class member

问题描述

我有一个类：

class M {
public:
    static std::string t[];
};

我想在不同的类（头文件）中使用M :: t：

with an initialization that comes later. I want to use the M::t later in a different class (header file):

class Use {
public:
    void f() { std::cout << M::t[0] << std::endl; }
};

有没有办法实现这一点，而不包括使用的头文件的整个类M？我理解forward声明不允许访问类成员，但这个美丽是一个静态的，所以它不应该是一个巨大的问题，编译器..

Is there any way to achieve this without including the whole class M for the header file of the Use? I understand that forward declarations do not allow accessing class members, however this beauty is a static one, so it shouldn't be a huge problem for the compiler..

推荐答案

不，你不能。您可以在标题中包含标头，或者在实现文件中分隔实现 Use :: f ，并包含 M 的标题。

No, you can't. You can either include the header in the header, or separate the implementation Use::f in an implementation file and include M's header there.

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