如何获取当前源路径在C ++ - Linux [英] How to get current source path in C++ - Linux

问题描述

我想要能够获取当前的源文件路径。

I want to be able to get the current source file path.

string txt_file = CURRENT_FILE_PATH +"../../txt_files/first.txt";
inFile.open(txt_file .c_str());

有办法获得CURRENT_FILE_PATH吗？
我不是指可执行路径。我的意思是代码运行的源文件的当前位置。

Is there a way to get the CURRENT_FILE_PATH ? I don't mean the executable path. I mean the current location of the source file that the code is running from.

非常感谢，
Giora。

Thanks a lot, Giora.

推荐答案

用于编译源文件的路径可通过标准C宏 __ FILE __ =http://gcc.gnu.org/onlinedocs/cpp/Standard-Predefined-Macros.html =nofollow> http://gcc.gnu.org/onlinedocs/cpp/Standard-Predefined-Macros。 html ）

The path used to compile the source file is accessible through the standard C macro __FILE__ (see http://gcc.gnu.org/onlinedocs/cpp/Standard-Predefined-Macros.html)

如果你给绝对路径作为编译器的输入（至少对于gcc） __ FILE __ 将保存文件的绝对路径，反之亦然。

If you give an absolute path as input to your compiler (at least for gcc) __FILE__ will hold the absolute path of the file, and vice versa for relative paths. Other compilers may differ slightly.

如果您使用GNU Make，并在变量 SOURCE_FILES 中列出源文件，像这样：

If you are using GNU Make and you list your source files in the variable SOURCE_FILES like so:

SOURCE_FILES := src/file1.cpp src/file2.cpp ...

您可以确保文件是通过它们的绝对路径，如下所示：

you can make sure the files are given by their absolute path like so:

SOURCE_FILES := $(abspath src/file1.cpp src/file2.cpp ...)

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