toupper / tolower + locale（german） [英] toupper/tolower + locale (german)

问题描述

如何将字符串（wstring）从小写字符转换为大写字符，反之亦然？
我搜索的网络，发现有一个STL函数std ::变换。

但是直到现在我hav'nt想出了如何给正确的locale对象，例如Germany_german到函数。
谁可以帮助吗？
我的代码如下：

  wstring strin = LABCÄÖÜabcäöü; 
 wstring str = strin; 
 locale loc（Germany_german）; // ???如何应用此??? 
 std :: transform（str.begin（），str.end（），str.begin（），（int（*）（int）tolower）; 
 // result：abcäöüabcäöü
  

字符ÄÖÜ和äöü（它就像Ae，Oe，Ue） p>

PS：我不喜欢大开关汗水，而且我知道BOOST有能力的一切，我更喜欢STL解决方案。 p>

提前感谢

糟糕

解决方案

你在Unix，看到 / usr / share / locale / 可用的语言环境看起来你想要de_DE.UTF-8 / code>。

但是 setlocale（LC_ALL，）;

如果我只是像这样设置默认语言环境，那么你的程序适用于我（我固定了一个闭函数），而不指定德国。

how to convert a string (wstring) from lowercase to uppercase characters and vice versa? I searched the net and found there is a STL-function std::transform.
But until now I hav'nt figured out how to give the right locale-object for example "Germany_german" to the function. Who can help please? my code looks like:

wstring strin = L"ABCÄÖÜabcäöü";
wstring str = strin;
locale loc( "Germany_german" ); // ??? how to apply this ???
std::transform( str.begin(), str.end(), str.begin(), (int(*)(int)tolower );
//result: "abcäöüabcäöü"

The characters ÄÖÜ and äöü (it's like Ae, Oe, Ue) will not be converted correctly.

P.S.: I don't prefer a big switch sweat and also I know BOOST is capable of everything, i would prefer a STL solution.

thanks in advance
Oops

解决方案

If you're on Unix, see /usr/share/locale/ for available locales. It looks like you want "de_DE.UTF-8".

But setlocale(LC_ALL, ""); should set the program to work in the system's locale, whatever it is.

Your program works for me (I fixed a close-paren) if I simply set the default locale like that, without specifying Germany.

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