精神规则中的定义函数给出警告 [英] Defining function in spirit rule gives warning

问题描述

qi :: repeat（1,2）在规则中的功能是给我warrning，我不想忽略该警告，所以我想优化这个代码，例如分隔规则正在执行规则中所执行的相同操作。

>

  std :: ifstream ifs（f： test.txt）; 
 std :: string line; 
 
 //在我的代码的头中
 std :: vector< unsigned long long> v_BF_Char; 
 
 
 // qi :: int_parser< uintmax_t，16> hex_int; 
 static qi :: uint_parser< unsigned long long，16，16，16> hex_int; 
 
 while（std :: getline（ifs，line））
 {
 typedef std :: string :: const_iterator It; 
 it begin = line.begin（），end = line.end（）; 
 
 //语法规则
 qi :: rule< It，unsigned long long（）> braced_hex ='&'>> qi :: repeat（1,2）[hex_int]>> '>'; 
 
 
 bool ok = qi :: phrase_parse（begin，end，
 *（'<'>> qi :: repeat（1,2）[hex_int] >>'），qi :: space，v_BF_Char）; 
  

并且想做这样的事。

  bool ok = qi :: phrase_parse（begin，end，
 braced_hex，qi :: space，v_BF_Char）; 
  

test.txt 包含

 < 51dc> < 04001C0180000000000000000EE317BC> 
< 05001C0180000000> < 04001C0180000000000000000EE317BC> 
< 51dc> < 30ea30f330ae30c330c8> 
< 0000> < fffd> 
< 003d> < 00a5> 
 <005d> < 00a6> 
< 005e> < 007d> 
< 005f> < 0303> 
< 0060> < 2019> ;. 
< 0061> < 005c> 
 <0062> < 2018> 
< 0063> < 007c> 
< 0064> < 007e> 
< 0068> < 2044> 
< 0069> < 0192> 
< 006a> < 00a7> 
< 006b> < 00a4> 
< 006c> < 201c> 
  

我的代码只在第二行工作，在向量中提取值， p>

解决方案

修复规则的公开属性：

  qi :: rule< It，std :: vector< unsigned long long>（）> braced_hex ='&'>> qi :: repeat（1,2）[hex_int]>> '>'; 
  

重复显示 hex_int的向量的曝光属性类型

现场演示：

strong> Live on Coliru

  #include< boost / spirit / include / qi.hpp> 
 #include< fstream> 
 
命名空间qi = boost :: spirit :: qi; 
 
 int main（）{
 std :: ifstream ifs（input.txt）; 
 
 //在我的代码的头中
 std :: vector< unsigned long long> v_BF_Char; 
 
 // qi :: int_parser< uintmax_t，16> hex_int; 
 static qi :: uint_parser< uint64_t，16，16，16> hex_int; 
 
 std :: string line; 
 while（std :: getline（ifs，line））
 {
 typedef std :: string :: const_iterator It; 
 it begin = line.begin（），end = line.end（）; 
 
 //语法规则
 qi :: rule< It，std :: vector< uint64_t>（）> braced_hex ='&'>> qi :: repeat（1,2）[hex_int]>> '>'; 
 
 bool ok = qi :: phrase_parse（begin，end，* braced_hex，qi :: space，v_BF_Char）; 
 assert（ok）; 
} 
 
 std :: cout<< Parsed：<< v_BF_Char.size（）<< 64bit elements\\\
; 
} 
  

列印：

 已解析：50 64位元素
  

对于该输入：

 < 1353cd278dd1f003636bc155006ac5ce> < 1e83b053032565f0> < d1e97c841e68153a5d82d57df3074a21> 
< 92adee538fd147a337ebc8a4fc8d0ad3> < 0ed9fb22ab42b3a4> < 756ad64486054d22c62329e8dcaef0c5> 
< 16eeaec1108b1159b49c6bf884564519> < b4b87d1fd1aa10af> < 1f710495fd863a1d191355adf1b33d5a> 
< 947ac523b4450ec26446840ccde3965b> < faa860f7763b23dc> < 571decbfd0fcfe9a4047f72c101b9d87> 
< 50d726028b79b1a531a2c3752a4fdde7> < 644e057721fa7fe1> < 6bf66d2e1ae50351db53eddcee5fae41> 
< 6916580258e94f2be66eb71f103d3023> < a427df9bd05edd6d> < d896cfe92e6634867fcab5c6fc2de60b> 
< 9e50d5c9cda9e9a2fbf78eeb10f3a6bd> < 9cff72edea319328> < 0aabc7f36fcd058a2dfa7bb94602919a> 
< 923832f107c94d4a04b1de96241fda14> < 003c7554390cabaf> < c43d58504fc6659bb226707efc0221b8> 
< 1040a8d23eac10e9e4b6abb2efcde1bd> < f38ac3906542529d> < ffbd836c54b0f498d358e4ea50170c94> 
< 7c4c6fd86a60cf7b4ac62faa0395c06b> < 61156478683a6b01> < fb92ef7030068f25471e8049fb0f7cd3> 
 





使用

生成的随机数据

  od -A none -t x8 -w256< / dev / urandom |头| awk'{print< $ 1 $ 2>< $ 3>< $ 4 $ 5> }'
  




qi::repeat(1,2) funtion in rule is giving me warrning and i dont want to ignore that warning so i want to optimized this code like separating the rule from the parsering method.

qi::phrase_parse is doing the same thing which is in the the rule but i want to sperate the rule and give rule to the pharse_parse funtion.

std::ifstream ifs("f:/test.txt");
 std::string line;

//In header in my code
std::vector<unsigned long long> v_BF_Char;


//qi::int_parser<uintmax_t, 16> hex_int;
static qi::uint_parser<unsigned long long, 16, 16, 16> hex_int;

while (std::getline(ifs, line))
{
    typedef std::string::const_iterator It;
    It begin = line.begin(), end = line.end();

    // rule for grammer
    qi::rule<It, unsigned long long()> braced_hex = '<' >> qi::repeat(1,2)[hex_int] >> '>';


    bool ok = qi::phrase_parse(begin, end,
           *('<' >> qi::repeat(1,2)[ hex_int ] >> '>'),  qi::space, v_BF_Char);

and want to do somthing like this

bool ok = qi::phrase_parse(begin, end,
           braced_hex ,  qi::space, v_BF_Char);

test.txt Contain

<51dc> <04001C0180000000000000000EE317BC>
<05001C0180000000> <04001C0180000000000000000EE317BC>
<51dc> <30ea30f330ae30c330c8>
<0000> <fffd>
<003d> <00a5>
<005d> <00a6>
<005e> <007d>
<005f> <0303>
<0060> <2019>
<0061> <005c>
<0062> <2018>
<0063> <007c>
<0064> <007e>
<0068> <2044>
<0069> <0192>
<006a> <00a7>
<006b> <00a4>
<006c> <201c>

My code is working for only 2nd line and extract values in vector but not other line values.

解决方案

Fix the rule's exposed attribute:

qi::rule<It, std::vector<unsigned long long>()> braced_hex = '<' >> qi::repeat(1,2)[hex_int] >> '>';

Repeat exposes a vector of hex_int's exposed attribute type

Live demo:

Live On Coliru

#include <boost/spirit/include/qi.hpp>
#include <fstream>

namespace qi = boost::spirit::qi;

int main() {
    std::ifstream ifs("input.txt");

    //In header in my code
    std::vector<unsigned long long> v_BF_Char;

    //qi::int_parser<uintmax_t, 16> hex_int;
    static qi::uint_parser<uint64_t, 16, 16, 16> hex_int;

    std::string line;
    while (std::getline(ifs, line))
    {
        typedef std::string::const_iterator It;
        It begin = line.begin(), end = line.end();

        // rule for grammer
        qi::rule<It, std::vector<uint64_t>()> braced_hex = '<' >> qi::repeat(1,2)[hex_int] >> '>';

        bool ok = qi::phrase_parse(begin, end, *braced_hex,  qi::space, v_BF_Char);
        assert(ok);
    }

    std::cout << "Parsed: " << v_BF_Char.size() << " 64bit elements\n";
}

Prints:

Parsed: 50 64bit elements

E.g. for this input:

<1353cd278dd1f003636bc155006ac5ce> <1e83b053032565f0> <d1e97c841e68153a5d82d57df3074a21>
<92adee538fd147a337ebc8a4fc8d0ad3> <0ed9fb22ab42b3a4> <756ad64486054d22c62329e8dcaef0c5>
<16eeaec1108b1159b49c6bf884564519> <b4b87d1fd1aa10af> <1f710495fd863a1d191355adf1b33d5a>
<947ac523b4450ec26446840ccde3965b> <faa860f7763b23dc> <571decbfd0fcfe9a4047f72c101b9d87>
<50d726028b79b1a531a2c3752a4fdde7> <644e057721fa7fe1> <6bf66d2e1ae50351db53eddcee5fae41>
<6916580258e94f2be66eb71f103d3023> <a427df9bd05edd6d> <d896cfe92e6634867fcab5c6fc2de60b>
<9e50d5c9cda9e9a2fbf78eeb10f3a6bd> <9cff72edea319328> <0aabc7f36fcd058a2dfa7bb94602919a>
<923832f107c94d4a04b1de96241fda14> <003c7554390cabaf> <c43d58504fc6659bb226707efc0221b8>
<1040a8d23eac10e9e4b6abb2efcde1bd> <f38ac3906542529d> <ffbd836c54b0f498d358e4ea50170c94>
<7c4c6fd86a60cf7b4ac62faa0395c06b> <61156478683a6b01> <fb92ef7030068f25471e8049fb0f7cd3>

random data generated with

od -A none -t x8 -w256 < /dev/urandom | head | awk '{ print "<" $1 $2 "> <" $3 "> <" $4 $5 ">" }'

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