cv :: Mat从外部原始指针数据，释放自身 [英] cv::Mat from external raw pointer data, releasing itself

问题描述

有从外部数据指针创建 cv :: Mat 的方法，但使该对象负责删除数据？

即，我有一个函数从 void *创建一个 cv :: Mat 指针，

  cv :: Mat createMat（）{
 
 * data =（...）; 
 
 cv :: Mat data_m（rows，cols，CV_8UC1，data）; 
 return data_m; 
} 
  

我希望我的返回 cv :: Mat 负责发布数据。 cv :: Mat :: data

所有OpenCV函数都需要 cv :: Mat :: data 是一个void *，所以你不能改变。如果你继承自 cv :: Mat 并且编写你自己的析构函数，你会变得与OpenCV不兼容，因为他们不返回你的派生类型。
我建议将 cv :: Mat 作为类的属性，并保留 std :: shared_ptr 或其他智能指针来管理底层 void * 的生命周期。
只需使用 std :: shared_ptr :: get（）
的原始指针初始化OpenCV矩阵 http://www.cplusplus.com/reference/memory/shared_ptr/get/ ，并确保他们具有相同的生命周期，即在同一个类。

is there a way of creating a cv::Mat from external data pointer, but making that object responsible for deleting the data?

i.e., I have a function creating a cv::Mat from a void * pointer,

cv::Mat createMat() {

  void *data = (...);

  cv::Mat data_m(rows, cols, CV_8UC1, data);
  return data_m;
}

and I want that my returned cv::Mat to be responsible for releasing the data. How can I do this?

解决方案

All OpenCV functions expect cv::Mat::data to be a void*, so you cannot change that. If you inherit from cv::Mat and write your own destructor, you become incompatible from OpenCV because they do not return your derived type. I would suggest to contain your cv::Mat as an attribute of a class, and keep a std::shared_ptr or other smart pointer to manage the lifetime of the underlying void*. Just initialize the OpenCV matrix with the raw pointer from the shared pointer with std::shared_ptr::get() http://www.cplusplus.com/reference/memory/shared_ptr/get/ and make sure they have the same lifetime, i.e. in the same class.

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