初始化一个静态const变量给我非模板const的模板定义 [英] Initializing a static const variable gives me template definition of non-template const

问题描述

这是我的代码：

#include <iostream>
class c{
    public:
    int y;
     c(int x,int p):y(x){
    std::cout<<"has been made"<<std::endl;  
    }


};



template<int x,typename B = void>
struct checkeven{

};


template<typename B>
struct checkeven<0,B>{
    typedef B type;
};



template<int x,int y,class = typename checkeven<x%2,int>::type>
struct t{
    static const c tee;

    static const inline c& initor(){

    return tee;
    }
};

template<int x,int y>
const c t<x,y>::tee(x,y);       //how do i initialize?


int main(int argc, char** argv) {

 //t<2,1>::initor();    
//t<2,2>::initor(); 

    return 0;
}

我尝试研究它，但我找不到任何东西，除了建议删除默认值重复。我想实现SFINAE，以确保第一个值是一个偶数。我有一个静态const变量，我想初始化。它工作正常没有我的默认类，但一旦我添加它，事情变得凌乱。如何初始化我的const静态成员？我也想知道为什么我的代码不工作。

I tried researching it about but i can't find anything except the suggestion to remove the default value duplicate. I want to implement SFINAE to make sure that the first value is an even number. I have a static const variable that i want to initialize. It was working fine without my default class but once i added it, things got messy. How do i initialize my const static member? I would also like to know why my code isn't working.

推荐答案

你需要专门化你的模板struct t ：

You need to specialize your template struct t like that :

template<int x, int y>
struct t<x,y, typename checkeven<x%2,int>::type> 
{
    static const c tee;

    static const inline c& initor(){

        return tee;
    }
};

使用它，你可以初始化你的变量tee：

Using this you'll be able to initialize your variable tee like that :

template<int x, int y>
const c t<x, y>::tee(x, y);

实例此处

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