C ++ stl pop不返回 [英] C++ stl pop doesn't return

问题描述

我经历过，stl pop函数不返回任何东西。

如何返回栈顶的元素并删除它？ >

top函数不是一个好的解决方案，因为它只返回顶级元素的引用...

解决方案

如果在弹出后不再需要该元素，

  with 
 container.top（）; 
 // remove it 
 container.pop（）; 
  

否则复制对象：

  Element e = container.top（）; 
 container.pop（）; // remove it 
 //随意使用e，你复制了它
  

如果你需要真正删除它手动，那么你没有使用任何类型的智能指针，这将问题移到另一个话题。

I have experienced, that the stl pop function doesn't return anything.

How can I return the top element of my stack and delete it?

The top function is not a good solution, because it returns only a reference of the top element...

解决方案

If you don't need the element anymore after popping it just

// use element with
container.top();
// remove it
container.pop();

Otherwise make a copy of the object:

Element e = container.top();
container.pop(); // remove it
// feel free to use e, you made a copy of it

If you need to really delete it manually then you are not using any kind of smart pointer, which moves the problem to another topic.

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