cout print十六进制而不是十进制 [英] cout print hex instead of decimal

问题描述

有人发现一个简单的 std :: cout 可能打印一个十六进制格式的值，当它应该格式化一个十进制（如整数）？

例如，我有一行如下：

std :: cout << _Agent [<目标<< ]仍然是
，在< （（target-> currWorker） - > getEntities（）。size（））<< entities
of worker [< target-> currWorker< ]<< std :: endl;

可打印：

_Agent [0x2c6d530]仍在 0x1 工人实体[0x2c520f0]

1 - 所述输出是有时十进制，有时候是十六进制

2-行为是smae如果我将（（target-> currWorker） - > getEntities（）。size（））更改为 ; currWorker） - > getEntities（）。size（））

所有提示？

$ b b

感谢

解决方案

您可能已经在代码的上下文中设置std :: cout在先前打印十六进制，忘记复位。例如：

  std :: cout<< std :: hex< 
 / * blah blah blah * / 
 std :: cout<<< 12; //这将以十六进制格式打印仍然
  

，所以你必须像下面这样

  std :: cout<< std :: dec<< 
  

以小数形式打印。

has it occurred to anyone that a simple std::cout might print a value in hex format when it is supposed to format just a decimal(like an integer)?

for example, I have a line as :

std::cout << "_Agent [" << target << "] is still among " << ((target->currWorker)->getEntities().size()) << " entities of worker[" << target->currWorker << "]" << std::endl;

which would print :

_Agent [0x2c6d530] is still among 0x1 entities of worker[0x2c520f0]

Note:

1-the said out put is sometime decimal and some times hex

2- the behaviour is smae even if I change ((target->currWorker)->getEntities().size()) to (int)((target->currWorker)->getEntities().size())

any hints?

thanks

解决方案

You probably have set std::cout to print hex in prior in the context of your code but forget to reset. For example:

std::cout<<std::hex<<12;
/*blah blah blah*/
std::cout<<12; //this will print in hex form still

so you have to do like the following

std::cout<<std::dec<<12;

to print in decimal form.

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