迭代时跳过相同的多重图片值 [英] Skip same multimap values when iterating

问题描述

有没有什么好的方法来实现所需的输出，而不必删除相同的值或创建另一个列表/向量等？我试图将在不同文档中找到的单词映射到其所需输出中显示的文档名称。

Is there any good way to achieve the desired output below without having to remove the same values or creating another list/vector etc? I am trying to map words found in different documents to their document names as shown in the desired output.

#include <iostream>
#include <fstream>
#include <string>
#include <map>
#include <sstream>

using namespace std;

multimap<string,string> inverts;
multimap<string,string>::iterator mit;
multimap<string,string>::iterator rit;
pair<multimap<string,string>::iterator,multimap<string,string>::iterator> ret;

int main(int argc, char* argv[])
{
ifstream infile;

for(int i=1;i<argc;i++)
{
    char* fname=argv[i];
    char line[1024];
    string buff;
    infile.open(fname);

    while(infile.getline(line,1024))
    {
        stringstream ss(line);
        while(ss >> buff)
            inverts.insert(pair<string,string>(buff,fname));
    }

    infile.close();

}

for(mit=inverts.begin();mit!=inverts.end();mit++)
{
    string first=(*mit).first;
    cout<<first;
    ret=inverts.equal_range(first);

    for(rit=ret.first;rit!=ret.second;rit++)
        cout<<" "<<(*rit).second;
    cout<<endl;

}


return 0;

}

Output is:

> ./a.out A B
cat A
dog A B
dog A B
fox A B
fox A B
lion B

I need this output:

> ./a.out A B
cat A
dog A B
fox A B
lion B

推荐答案

您可以将 inverts 变更为 map< string，set< string> ;> ，将每个词映射到出现的文件名集。

You could change inverts into map<string,set<string>>, mapping each word to the set of file names where it appears.

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