需要帮助，以停止程序终止，无需用户同意 [英] Need help to stop program terminating without users consent

问题描述

下面的代码应该如下：

1. 创建用户指定的列表

1. create list specified by the user

要求用户输入号码

ask user to input number

<在列表中，显示数字* 2，返回到步骤2

3.a) if number is on the list , display number * 2, go back to step 2

3.b）如果数字不在列表上，终止程序

3.b) if number isn't on the list, terminate program

然而，步骤3.a）也会终止程序，这会破坏while循环的目的。

HOWEVER step 3.a) will also terminate the program, which is defeating the purpose of the while loop.

代码：

#include <iostream>
#include <array>
using namespace std;
int main()
{
cout << "First we will make a list" << endl;

array <int, 5>list;
int x, number;
bool isinlist = true;

cout << "Enter list of 5 numbers." << endl;

for (x = 0; x <= 4; x++)
{
    cin >> list[x];
}
while (isinlist == true)
{
    cout << "now enter a number on the list to double" << endl;
    cin >> number;

    for (x = 0; x <= 4; x++)
    {
        if (number == list[x])
        {
            cout << "The number is in the list. Double " << number << " is " << number * 2 << endl;
        }
        else
            isinlist = false;
    }
}
return 0;
}

有人可以帮我解决这个问题吗？

Please can someone help me to resolve this ?

推荐答案

我建议您将步骤3的功能封装到单独的函数中。你可以如下定义一个函数，然后在main函数的适当位置调用它。

I would suggest that you encapsulate the functionality of step 3 into a separate function. You could define a function as follows, and then call it at an appropriate location in the main function.

void CheckVector(vector<int> yourlist)
{
  .... // Take user input for number to search for
  .... // The logic of searching for number. 
  if (number exists)
  {
    // cout twice the number
    // return CheckVector(yourlist)
  }
  else
    return;
}

同样的功能可以用 goto 语句，避免需要一个函数。但是，使用 goto 被认为是不好的做法，我不会推荐它。

The same functionality can be implemented with a goto statement, avoiding the need for a function. However, using goto is considered bad practice and I won't recommend it.

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