我如何设置一个断点on operator&与GDB [英] How do I set a breakpoint on operator< with GDB

问题描述

基本上是什么标题说。我有一个函数：

  bool操作符< （... lhs，... rhs）
  

'b operator<（...）'给我错误：

 命令中的格式化模板规范
  

如何停止GDB的思考<是模板开放？我试图设置一个断点的行号，以及，但这个定义是在头文件，并且由于某种原因，GDB认为行号不存在于头文件中。

GDB 6.8

解决方案

你可以先打印所有出现的

。

技术将工作，不管你的函数定义是在 .h 或 .cpp 文件， code> g ++ 使用 -g

  $ gdb test 
 
（gdb）p'operator<'
 $ 1 = {bool（MyClass& MyClass&）} 0x4009aa< operator<（MyClass& MyClass&）> 
 
（gdb）b * 0x4009aa 
断点1在0x4009aa：文件test.h，第5行。
 
（gdb）r 
启动程序： /home/agururaghave/.scratch/gdb-test/test 
 
断点1，operator< （obj1 = ...，obj2 = ...）at test.cpp：6 
 6 friend bool operator< （MyClass& obj1，MyClass& obj2）{
  

我测试了以下代码： / p>

  / * test.h * / 
 #include< iostream> 
 class MyClass {
 public：
 friend bool operator< （MyClass& obj1，MyClass& obj2）{
 std :: cout< operator< << \\\
; 
 return true; 
} 
}; 
 
 / * test.cpp * / 
 #includetest.h
 int main（）{
 MyClass myObj1; 
 MyClass myObj2; 
 
 bool result = myObj1< myObj2; 
 
 std :: cout<<结果< \\\
; 
 
 return 0; 
} 
  

Basically what the title says. I have a function:

bool operator< (... lhs, ... rhs)

that I would like to break on. 'b operator<(...)' gives me the error:

malformed template specification in command

How can I stop GDB from thinking the < is a template opener? I've tried to set a breakpoint by line number as well, but this definition is in a header file, and for some reason, GDB thinks that line number doesn't exist in the header file.

GDB 6.8

解决方案

You could first print all occurrences of operator <, grab the address of the function you're interested and set a breakpoint on it.

NOTE: This technique would work irrespective of your function definition is in .h or .cpp file as long as you have compiled with g++ using -g

$ gdb test

(gdb) p 'operator <'
$1 = {bool (MyClass &, MyClass &)} 0x4009aa <operator<(MyClass&, MyClass&)>

(gdb) b *0x4009aa
Breakpoint 1 at 0x4009aa: file test.h, line 5.

(gdb) r
Starting program: /home/agururaghave/.scratch/gdb-test/test 

Breakpoint 1, operator< (obj1=..., obj2=...) at test.cpp:6
6           friend bool operator < ( MyClass &obj1, MyClass &obj2 ) {

I tested out with the following code:

/* test.h */
#include <iostream>
class MyClass {
public:
    friend bool operator < ( MyClass &obj1, MyClass &obj2 ) {
        std::cout << "operator <" << "\n";  
        return true;
    }
};

/* test.cpp */    
#include "test.h"
int main() {
    MyClass myObj1;
    MyClass myObj2;

    bool result = myObj1 < myObj2;

    std::cout << result << "\n";

    return 0;
}

这篇关于我如何设置一个断点on operator&与GDB的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！